Zadanie 22 21 20
donkey and mule, objuczone bags, walked with difficulty up the hill. The donkey began to complain against the weight of the mud which has imposed upon him
man. But the mule And he said
- Animal lazy, how can you complain? If I
took one of your bags, I had them two times more than you, and if thou take one of mine, until we
equally. How many bags he carried
ass?
solution to the problem
x - number of bags of ass
y - the number of bags mule
get the system of equations with two unknowns:
y + 1 = 2 (x - 1)
y - 1 = x + 1
Sunday, December 21, 2008
Saturday, December 20, 2008
Good Things To Write In A Wedding Presant
Three Graces bring apples, each with an equal quantity. Meet the Muses nine, at their request bestow any
muse the same amount of apples. After the division of each and every muse grajca had the same quantity of apples. How many apples would each
from grace before the break?
solution to the problem
all goddesses, and there were a total of 12, after the division had an equal number of apples.
So the total number of apples must be a multiple of 12, with the result that each of the three
gracyj had before dividing the number of apples is divisible by 4
We also know that every grace bestowed nine muses the same amount of apples, which is
this number may not be less than the 9th The first multiple of 4
greater than 9 is 12 This figure will therefore be sought, as if every grace
da muse one apple each, to every grace remain 3 apples, and each will receive 3 Muses
apples. The solution so that all tasks are multiples of the 12th
Monday, December 15, 2008
How Long Can You Cellar Moet
Zadanie Zadanie19
Two cyclists initially located within twenty miles apart. Going to the meeting, each
a speed of 10 km / h. At the time of the initial fly off from the front wheel of one cyclist and flies with
speed of 15 km / h for a meeting with the other. Dolatuje to him, turns and flies to meet the first, and then again after
recycled, and so on, until he is crushed between the front wheels of two bicycles. What is the distance to beat
fly?
solution to the problem
This task can be solved in two ways. You can calculate the length of the flight
flies between successive meetings with cyclists and wysumować
infinite series, but a second, much easier way.
Just a note that cyclists will meet after an hour ride, so fly
also has to fly for an hour, and that the years with a constant speed of 15
km / h, within 1 hour fly 15 km.
Two cyclists initially located within twenty miles apart. Going to the meeting, each
a speed of 10 km / h. At the time of the initial fly off from the front wheel of one cyclist and flies with
speed of 15 km / h for a meeting with the other. Dolatuje to him, turns and flies to meet the first, and then again after
recycled, and so on, until he is crushed between the front wheels of two bicycles. What is the distance to beat
fly?
solution to the problem
This task can be solved in two ways. You can calculate the length of the flight
flies between successive meetings with cyclists and wysumować
infinite series, but a second, much easier way.
Just a note that cyclists will meet after an hour ride, so fly
also has to fly for an hour, and that the years with a constant speed of 15
km / h, within 1 hour fly 15 km.
Friday, December 12, 2008
What Would Wwf Cards Be Worth
Zadanie 18
Two villagers to the market brought together 100 eggs, each a different number. Both received the same amount of money for
sold all the eggs. The first said:
If I had enough eggs, if you brought me to the market, it zarobiłabym 15 grajcerów.
The second replied:
If I had, in turn, are the eggs, which you brought me a zarobiłabym
623grajcera. How many eggs
brought to the market every peasant?
solution to the problem
Let X be the number of eggs, which first brought to market wieśnaczka. Thus, the second peasant brought
100 - x eggs. Price of one egg in the first peasant is
15100-x, and in the other 623x
now calculate how much money they get for each of the peasant women sold eggs.
first received 15100-x
· x, while the other
623x
° (100-x)
get the equation
15100-x, x = 623x
° (100-x)
.
45x2 = 20 (100 - x) 2
x = 40
Two villagers to the market brought together 100 eggs, each a different number. Both received the same amount of money for
sold all the eggs. The first said:
If I had enough eggs, if you brought me to the market, it zarobiłabym 15 grajcerów.
The second replied:
If I had, in turn, are the eggs, which you brought me a zarobiłabym
623grajcera. How many eggs
brought to the market every peasant?
solution to the problem
Let X be the number of eggs, which first brought to market wieśnaczka. Thus, the second peasant brought
100 - x eggs. Price of one egg in the first peasant is
15100-x, and in the other 623x
now calculate how much money they get for each of the peasant women sold eggs.
first received 15100-x
· x, while the other
623x
° (100-x)
get the equation
15100-x, x = 623x
° (100-x)
.
45x2 = 20 (100 - x) 2
x = 40
Wednesday, December 10, 2008
What Is D Cost Heart Gold Rom In India
Zadanie17
Within four weeks, 12 cows eat the grass of the meadow with an area of \u200b\u200b313
jugiera. We assume that during this whole time the grass is growing steadily. Within nine weeks 21
cow eats the grass of the meadow area of \u200b\u200b10 jugierów. How many cows eat grass from a meadow
jugierów surface 24 within 18 weeks?
solution to the problem
Let x is the amount of grass on the surface of one jugiela, and y is the amount of growth may
new grass on the surface of one jugiera within one week. Then, on the surface
313
jugiera is
103x
grass, and stirred for four weeks on the pasture grows
4,103 's
grass. From this it follows that a cow eats in a week
4103 y
103 x 4.12
grass.
the other hand, the amount of grass in a meadow with an area equal to 10 jugierów is 10x, and within nine weeks of
meadow grass grows 90Y. One cow in a week so eats
90Y 10 x 9.21
grass.
get the equation
403y
103 x
4.12
90Y = 10 x 9.21
Hence 9 · 21 ·
103
(4y + x) = 4 ⋅ 12 * 10 (9Y + x).
get x = 12Y
One cow eats in a week
109Y
grass.
amount of grass for 24 jugierach equals 24x = 24 ° 12 · y
Within 18 weeks on the meadow grows 24 ° 18 's grass.
total amount of grass, which is enough for 18 weeks equals 24 ° 12
's + 24 ° 18' s = 24 ° 30 ° y
Within 18 weeks a cow eats
109Y
· 18 = 20Y grass.
Grass is therefore sufficient for
24.30
20Y y = 36 cows.
Within four weeks, 12 cows eat the grass of the meadow with an area of \u200b\u200b313
jugiera. We assume that during this whole time the grass is growing steadily. Within nine weeks 21
cow eats the grass of the meadow area of \u200b\u200b10 jugierów. How many cows eat grass from a meadow
jugierów surface 24 within 18 weeks?
solution to the problem
Let x is the amount of grass on the surface of one jugiela, and y is the amount of growth may
new grass on the surface of one jugiera within one week. Then, on the surface
313
jugiera is
103x
grass, and stirred for four weeks on the pasture grows
4,103 's
grass. From this it follows that a cow eats in a week
4103 y
103 x 4.12
grass.
the other hand, the amount of grass in a meadow with an area equal to 10 jugierów is 10x, and within nine weeks of
meadow grass grows 90Y. One cow in a week so eats
90Y 10 x 9.21
grass.
get the equation
403y
103 x
4.12
90Y = 10 x 9.21
Hence 9 · 21 ·
103
(4y + x) = 4 ⋅ 12 * 10 (9Y + x).
get x = 12Y
One cow eats in a week
109Y
grass.
amount of grass for 24 jugierach equals 24x = 24 ° 12 · y
Within 18 weeks on the meadow grows 24 ° 18 's grass.
total amount of grass, which is enough for 18 weeks equals 24 ° 12
's + 24 ° 18' s = 24 ° 30 ° y
Within 18 weeks a cow eats
109Y
· 18 = 20Y grass.
Grass is therefore sufficient for
24.30
20Y y = 36 cows.
Saturday, December 6, 2008
1978 Trojan Long Point Boat
Zadanie16
Two monkeys sitting on a tree: one for the its top, the second
height of 10 feet on the ground. The second monkey, trying to drink water from a distant source in
about 40 yards, got off the tree, at that time the first
monkey jumped from the top directly to the same source after
hypotenuse. The distance traveled by the monkeys was the same. With
how much the first monkey jumped from a tree?
Solution:
The result was a monkey jump right triangle.
Since the distance was the same, the hypotenuse is equal to 50 cubits
. Distant source is 40 yards, so much is one of the
hypotenuse. Using the Pythagorean theorem come quickly,
that tree height is 30 cubits.
Two monkeys sitting on a tree: one for the its top, the second
height of 10 feet on the ground. The second monkey, trying to drink water from a distant source in
about 40 yards, got off the tree, at that time the first
monkey jumped from the top directly to the same source after
hypotenuse. The distance traveled by the monkeys was the same. With
how much the first monkey jumped from a tree?
Solution:
The result was a monkey jump right triangle.
Since the distance was the same, the hypotenuse is equal to 50 cubits
. Distant source is 40 yards, so much is one of the
hypotenuse. Using the Pythagorean theorem come quickly,
that tree height is 30 cubits.
Thursday, December 4, 2008
Rare Autoimmune Diseases
task ... Jan Kochanowski
Find three of these numbers, the sum and the sum of each pair of numbers is a square
a different number.
Solution: These numbers are: 80, 320, 41
Find three of these numbers, the sum and the sum of each pair of numbers is a square
a different number.
Solution: These numbers are: 80, 320, 41
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